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Death Blossom Sudoku Technique

ExtremeClassic + KillerStep 36 of 384 min read

Death Blossom attaches one Almost Locked Set to every candidate of a single cell and reads what the whole flower has in common. The cell is the stem, the sets are the petals, and if every petal contains the same digit, that digit is forced into one of them no matter what the stem turns out to be.

What the pattern is

An Almost Locked Set is a group of n cells in one unit carrying n + 1 candidates. Remove one of its digits and it locks: the remaining cells must use every remaining digit.

A Death Blossom needs three things:

  • A stem cell with k candidates, usually two or three.
  • One petal per stem candidate: an Almost Locked Set containing that digit, where every copy of that digit inside the petal sees the stem.
  • A digit z, not a stem candidate, present in all of the petals.

Set the stem to any of its values. That value is knocked out of the matching petal, the petal locks, and it is forced to place z. Every value of the stem leads to some petal holding z, so z cannot live in a cell that sees all of the z candidates across all petals.

ALS-XZDeath Blossom
Sets involvedtwoone per stem candidate
What links thema restricted common digita stem cell
Conclusionone of the two sets holds zone of the petals holds z

When to look for it

Look once you are comfortable spotting Almost Locked Sets and a Legendary grid still refuses to move. Bivalue stems are the practical case: two petals, two branches, quick to verify. The stem itself is often an ordinary pair you have already stared at for ten minutes.

How to apply it, step by step

  1. Pick a cell with two or three candidates as the stem.
  2. For each stem candidate, find a nearby Almost Locked Set containing that digit where every copy of it sees the stem.
  3. List the digits each petal holds besides the stem digit.
  4. Take a digit that appears in every petal and is not a stem candidate. That is z.
  5. Mark every z candidate in every petal.
  6. Remove z from any cell outside the stem and petals that sees all of those marks.

A worked example

  1. Easier techniques are used up. Look at E5, which can only be 5 or 7.

  2. E5 is the stem. It is either 5 or 7, and each option gets its own petal.

  3. Petal for 5: D7, E7, E8 and E9 in box 6 hold 1, 5, 6, 7 and 8, five digits in four cells. That is an almost locked set.

    Its 5s sit in E7, E8 and E9, all in row E with the stem.

  4. Petal for 7: C2 and C5 in row C hold 1, 5 and 7, three digits in two cells.

    Its only 7 is C5, in column 5 with the stem.

  5. If E5 is 5, the box 6 petal loses its 5s. Four cells are left with 1, 6, 7 and 8, so one of D7 and E7 is 1.

  6. If E5 is 7, C5 cannot be 7. C2 and C5 are left with 1 and 5, so one of them is 1.

  7. Either way a 1 lands in D7, E7, C2 or C5.

    1 removed from C7 because it sees D7 and E7 in column 7 and C2 and C5 in row C.

Easier techniques are used up. Look at E5, which can only be 5 or 7.

The stem is E5 . The petal for 5 is D7, E7, E8 and E9 in box 6: four cells holding 1, 5, 6, 7 and 8, so an almost locked set. Its 5s are in E7, E8 and E9, all in row E with the stem. The petal for 7 is C2 and C5 in row C, holding 1, 5 and 7. Its only 7 is C5, in column 5 with the stem.

If E5 is 5, the box 6 petal loses its 5s and is left with 1, 6, 7 and 8, so D7 or E7 is 1. If E5 is 7, C5 cannot be 7, so C2 and C5 are and one of them is 1. Either way a 1 lands in D7, E7, C2 or C5. C7 sees D7 and E7 through column 7 and C2 and C5 through row C, so C7 loses its 1.

Common mistakes

  • Using a petal that does not contain the stem digit it is supposed to answer. Each petal must cover exactly one branch.
  • Choosing z from the stem's own candidates. It has to be independent of the stem's value.
  • Letting a petal overlap the stem cell or another petal.
  • Eliminating from cells that see the z marks of only one petal.

Where you meet it

Death Blossom is an extreme-tier tool and appears mainly in Legendary puzzles. It behaves like a very short forcing structure with the branching hidden inside the petals, which is why solvers who are fluent with XY-Chains usually find it easier than they expect.

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